Hi Friends,
For Hand Shake Problems
Four Types:
N given no of people.
‘No cyclic’ sequence “n-1” will be the answer
‘Cyclic Sequence “n” will be the answer
how many set they are asking “ n/3” will be the answer
hand shake with each other n(n-1)/2 will be the answer
A person run from A to B.He took ¼ of the time less to reach B when compare to run at normal Speed.Then how many percentage he has increased his speed?
Suppose the person take ‘x’ hours. Now take only ‘ 3/4x’ time only….
Time 4x:3x
They are asking speed so speed and time are indirectional proportational
Now indirectional so, speed 3x:4x
Speed percentage= x/3x * 100; i.e., 100/3 =33.33%
If a pipe can fill the tank within 6hrs.But due to leak it takes 30 min more. Now the tank is full then how much time will it take to empty the tank throught the leak?
Fill the tank ‘x’ hours;
Empth the tank ‘y’ hours
They will both fill and empty in the same problem x*y/y-x;
2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?
For this,
2orange 3bananas 4apples = 15
3orange 2bananas 1apple = 10
5 orange 5 bananas 5apple = 25
5(1 orange 1 banana 1 apple)=25
1 orange 1 banana 1 apple = 5
3(1 orange 1 banana 1 apple)=15
A man spends half of his salary on household expenses, 1/4th for rent, 1/5th for travel expenses; the man deposits the rest in a bank. If his monthly deposits in the bank amount 50, what is his monthly salary?
Salary “X”
Therefore
x-(x/2 + x/4 + x/5 ) = 50; like wise…….
Alok and Bhanu play the following min-max game. Given the expression
N = 9 + X + Y - Z
Where X, Y and Z are variables representing single digits (0 to 9), Alok would like to maximize N while Bhanu
would like to minimize it. Towards this end, Alok chooses a single digit number and Bhanu substitutes this for a variable of her choice (X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the value. Finally Alok proposes the value for the remaining variable. Assuming both play to their optimal strategies, the value of N at the end of the game would be
For this type
X -Y – Z = 2
X + Y – Z= 11
X * Y – Z= 18
A Sheet of paper has statements number from 1 to 20. Statement n says "At least n of the statements on this sheet are true". Which statements are true and which are false.
a. The even no statements are true and the odd no statements are false.
b. The 1st 13 statements are false and rest are true.
c. The 1st 6 statements are true and rest are false
d. The odd no statements are true and even no. are false.
Solution: This type of question was repeated 3 times but for different case.
For this type of Questions, follow this:
At least- first half are true, Last half are false
Exactly- Last second one is true or (N-1)th Statement is true
Almost- All are true.
The pace length P is the distance between the rear of two consecutive footprints. For men, the formula, n/P = 144 gives an approximate relationship between n and P where, n = number of steps per minute and P = pacelength in meters. Bernard knows his pace length is 164cm. The formula applies to Bernard's walking. Calculate Bernard's walking speed in kmph.
n = number of steps per minute
P = pace length in meters
Now n= 144* 1.64
Now find distance = 144*1.64*1.64
Now change into kmph 144*1.64*1.64 *60/1000;
The hare starts after the tortoise has covered 1/5 of its distance
and that too leisurely3. A hare and a tortoise have a race along a
circle of 100 yards diameter. The tortoise goes in one direction and
the. The hare and tortoise meet when the hare has covered only 1/8 of
the distance. By what factor should the hare increase its speed so as to
tie the race?
in this problem atfirst find the ratio of the distance left to cover the
turtle and distance by the hare. means-(87.5-20)/12.5=5.4
and then 87.5/12.5=7
and multiply these two 5.4*7=37.8
Six friends decide to share a big cake. Since all of them like the
cake, they begin quarreling who gets to first cut and have a piece of
the cake. One friend suggests that they have a blindfold friend choose
from well shuffled set of cards numbered one to six. You check and find
that this method works as it should simulating a fair throw of a die.
You check by performing multiple simultaneous trials of picking the
cards blindfold and throwing a die. You note that the number shown by
the method of picking up a card and throwing a real world die, sums to a
number between 2 and 12. Which total would be likely to appear more
often 8,9 or 10?
Always minimum number will be the answer…………
Adam sat with his friends in the Chinnaswamy stadium at Madurai to watch the 100 metres running race organized by the Asian Athletics Association. Five rounds were run. After every round half the teams were eliminated. Finally, one team wins the game. How many teams participated in the race?
Total round = n;
How many teams participated = 2^n;
How many matches played = 2^n -1;
A Roman was born the first day of the 35th year before Christ and died the first day of the 35th year after Christ. How many years did he live?
Before Christ birth - 35
Christ birth year - 1
After Christ birth - 35
So answer is 71.
1. Anoop managed to draw 7 circles of equal radii with their centres on the diagonal of a square such that the tw o extreme circles touch two sides of the square and each middle circle touches two circles on either side. Find the ratio of the radius of the circles to the side of the square
Options
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Ans: |
Let the radius of each circle = r
To find the diagonal of the square at the bottom left and top right of the bigger square, lets use the age-old Pythagoras Theorem,
r2 + r2 = d12
2r2 = d12
d1 = √2*r
So, Diagonal of the square = d1+r + 5*2r + r + d1
= 2d1 + 12r
= 2*√2*r + 12 r
= (2√2+12) r
Let the side of the square = s and the diagonal = d
s2 + s2 = d2
2s2 = d2 = ((2√2+12) r)2
Taking square root throughout, we get,
√2 * s = (2√2+12) r
So, r/s = √2/(2√2+12)
= r/s = 1/(2 + 6√2)
| There are 9 weights like 16,19.156.26, 106,15,24,36 (in kg). There are three persons like rohit, sameer and imran. each lifts 3 types of weights. Rohit”s total lifted weight is 2 times than the weight lifted by rohit. What is the weight lifted by imran? | ||
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| Total weight=16+19+156+26+106+15+24+36=398 kg |
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) There are 7 meetings A,B,C,D,E,F,G .one meeting should happen in one day. Meeting A is on Sunday c and d meetings should happen after B. Then E ,F,G meetings should occur in three conjucutive days. And meeting g is on Saturday. Then meeting d should occur on which day?
sun->A
Mon->B
Tue->C or D
Wed->C or D
Thu->E or F
Fri->E or F
Sat->G
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| A garrison of 3300 men has provisions for 32 days when supplied at the rate of 850 g per head. At the end of 7 days, reinforcement arrives, and it is found that the provisions can last for 17 days more when supplied at the rate of 825 g per head. What is the strength of the reinforcement | |
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| 1700 |
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| 1000 |
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| 2700 |
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| 3000 |
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| 3300 men -> 32 days -> 850 g/head | ||
If on an item a company gives 25% discount, they earn 25% profit. If they now give 10% discount then what is
If on an item a company gives 25% discount, they earn 25% profit. If they now give 10% discount then what is the profit percentage.
(a) 40% (b) 55% (c) 35% (d) 30%
Let written price = $100
Discount = 25% of 100 = $25
Selling price = $100 - $25 = $75
Discount = 10% of $100 = $10
Selling price = $100 - $10 = $90
Selling price $75 gives 25% profit
Therefore selling price $90 gives
25/75 * 90 = 30% profit
Ans: d) 30%
10.A bus started from bus stand at 8.00am, and after 30 minutes staying at
destination, it returned back to the bus stand. The destination is 27 miles from
the bus stand. The speed of the bus is 18mph. In return journey bus travels
with 50% fast speed. At what time it returns to the bus stand?
Sol: 11.00am
For this bus problem we get that the bus travel 9miles in 30min. As the dest. is 27miles the bus reaches the dest in 90mini.e.,1 1/2 hr so the time is 9.30 by the time the bus reaches the dest.n it stays there till 10.n It is give that return speed is
50% fast speed so 18+9=27miles per hour becomes the new speed.so by 11 it comes back to the bus stand.
The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
| 23 years | 24 years | ||
| 25 years | None of these |
Answer & Explanation
Answer: Option A
Explanation:
Let the average age of the whole team by x years.
11x - (26 + 29) = 9(x -1)
11x - 9x = 46
2x = 46
x = 23.
So, average age of the team is 23 years.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
| 1 hour | 2 hours | ||
| 3 hours | 4 hours |
Answer: Option A
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
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| 600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
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The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
| 240 | 270 | ||
| 295 | 360 |
Answer: Option B
Explanation:
Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
| metal strip of width ‘x’ cm. 2 metal strips are placed one over the other, then the combine length of 2 strips is ‘y’. If ‘z’ strips are placed in that manner. What is the final width of that arrangement? | ||
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| The length is not changing as strips are placed one above the other. | ||
1. Peter and Paul are two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when Peter was as old as Paul is now. What is the present age of Peter?
a)8 b)20 c)16 d)15
Options
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| 20 |
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| 16 |
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| 15 |
let pauls age be 'a' and peters be 'e'
e+a=35 (given)
e=35-a ------eq1
when peter was as old as paul that is when peter's age was 'a' i.e e-(e-a) [for example if e was 9 and a was 5, e-a is 4,9-4=5 so e-(e-a)]
pauls age was a-(e-a) =2a-e
now peters age is e=2(2a-e)
e=4a-2e
3e=4a
3(35-a)=4a
105-3a=4a
a=15
hence e=20 
(OR)
LET SOME N YRS BACK AGES OF PETER ND PAUL ARE 2X,X.......
NOW THEY ARE 2X+N,X+N
ND 2X+N+X+N=35
3X+2N=35
POSSIBLE VALUES ARE X=5,N=10
HENCE PRESENT AGE OF PETER IS 20
Smita was makin 1 design(again some nonsence) size of larger cube to be made is 5*5*5 using smaller cubes of 1*1*1. She created solid larger cube Then she decided to make hollow cube. Then how many 1*1*1 cubes required to make hollow larger cube
Ans= 104
Explanation: (25+25)+(15+15)+(12+12)=104
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When Rajeev was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Rajeev's brother is 6 years older than Rajeev and his mother is 3 years younger than his father, how old was Rajeev's sister when Rajeev was born? | |||
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At the college entrance exam, a candidate is admitted according to whether he has passed or failed the test. Of the candidates who are really capable, 80 % pass the test and of the incapable, 25 % pass the test. Given that 40 % of the candidates are really capable, then the proportion of the really capable students who can pass the test to the total students who can pass is about | ||||
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| Consider the total students as 100; | ||
| The bacteria had a probability of splitting into three and a probability to die is one third oftotal bacteria..Let the probability be P. Some of them survived wit probability 1/5. then wicamong the following relation is true? | ||||||||||
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| First option is correct as , probability to die is 1/3 and surviving is remaining which is 1/5 *3 as it becomes 3 times | ||
| a manufacturer undertakes to supply 2000 pieces of particular component at Rs.25 per piece. according to his estimates even if 5% fail to pass the quality test, then he will make a profit of 25%.however as it turned out 50% of the components were rejected. What is the loss of the manufacturer? | ||||||||||||||||||
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| Sale according to 5% loss = 1900*25 = 47500 |
A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg. How many 2kg packets are there?
(a) 100 (b) 114 (c) 200 (d) 208
114.
A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg.
If all boxes are of 1 kg, wt will be 150 kg.
Diff = 264-150 =114.
so 114 boxes have wt of 2 kg instead of 1 kg.
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